How do you find the absolute value of z = 2 - 6i?

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Answer 1 · 2016-09-23T17:20:23

The Ab. Val. $=2sqrt10~~6.3244$ .

We denote The Absolute Value of a Complex No. $z=a+ib$ by |z|, &,

it is defined by,

$|z|=|a+ib|=sqrt(a^2+b^2).$

In our case,

$|z|=|2-6i|=sqrt{2^2+(-6)^2}=sqrt40=2sqrt10$ .

Taking, #sqrt10~~3.1622,

The Ab. Val. $=2sqrt10~~6.3244$ .