# How do you find the antiderivative of 4/x^2?

Apr 14, 2015

$= - \frac{4}{x} + C$

Solution

$\int \frac{4}{{x}^{2}} \mathrm{dx}$

$= \int 4 {x}^{-} 2 \mathrm{dx}$

$= 4 \int {x}^{-} 2 \mathrm{dx}$

$= 4. \frac{{x}^{- 2 + 1}}{- 2 + 1} + C$

$= 4. \frac{{x}^{-} 1}{- 1} + C$

$= - \frac{4}{{x}^{1}} + C$

$= - \frac{4}{x} + C$