Question

How do you find the antiderivative of `4/x^2`?

Answer 1

`=-4/(x)+C`

Solution

`int4/(x^2)dx`

`=int4x^-2dx`

`=4intx^-2dx`

`=4.(x^(-2+1))/(-2+1)+C`

`=4.(x^-1)/(-1)+C`

`=-4/(x^1)+C`

`=-4/(x)+C`