How do you find the antiderivative of #f(x)=x^5#?

1 Answer
Feb 17, 2017

Have a look:

Explanation:

You are looking for a function that once derived will give you #x^5#;
a good candidate would be #x^6# in fact if you derive it you get: #6x^5#.
it is not really equal but we can use a little trick and say (to get rid of the #6#) that our antiderivative will be:
#F(x)=1/6x^6+c#
the #c# is a constant that we add to be sure to cover all the possibilities and anyway, during the derivation, it will desappear (our antiderivative could be, for example, #F(x)=1/6x^6+7# or #F(x)=1/6x^6+345# or other number so that when you derive it you will still get #x^5#!!!).

As a general rule the antiderivative of #x^n# can be found as:

#x^(n+1)/(n+1)+c#