# How do you find the area of the surface generated by revolving the curve #y=x^3/3# on the interval [0,3], about the x-axis?

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I'm unsure how to answer this, having a bit of trouble. This is in Calculus 2.

I'm unsure how to answer this, having a bit of trouble. This is in Calculus 2.

##### 1 Answer

Apr 11, 2018

See the answer below: