How do you find the asymptotes for #f(x)=(-x)/(x-4)#?
1 Answer
Jul 23, 2016
vertical asymptote x = 4
horizontal asymptote y = -1
Explanation:
The denominator of f(x) cannot be zero as this would be undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.
solve: x - 4 = 0 → x = 4 is the asymptote
Horizontal asymptotes occur as
#lim_(xto+-oo),f(x)toc" (a constant)"# divide terms on numerator/denominator by x
#(-x/x)/(x/x-4/x)=(-1)/(1-4/x)# as
#xto+-oo,f(x)to(-1)/(1-0)#
#rArry=-1" is the asymptote"#
graph{(-x)/(x-4) [-10, 10, -5, 5]}