How do you find the average value of #f(x)=1/(x^2+1)# as x varies between #[-1,1]#?
1 Answer
Nov 7, 2016
Evaluate
Explanation:
The average value of
#1/(b-a) int_a^b f(x) dx#
We also need:
or, you may prefer the notation
The average value is
# = 1/2[pi/4 - (-pi/4)]#
# = pi/4#