How do you find the center and radius for #(x + 14)^2 + (y - 6)^2 = 9#?
centre = (-14 ,6), radius = 3
The standard equation of a circle is.
where (a ,b) are the coordinates of the centre and r, the radius.
The equation here is in this form and by comparison.
#a=-14,b=6" and " r^2=9rArrr=3#
#rArr" centre " =(-14,6)" and " r=3#