How do you find the center and radius for (x + 14)^2 + (y - 6)^2 = 9?

Aug 24, 2016

centre = (-14 ,6), radius = 3

Explanation:

The standard equation of a circle is.

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}} \textcolor{w h i t e}{\frac{a}{a}} |}}}$
where (a ,b) are the coordinates of the centre and r, the radius.

The equation here is in this form and by comparison.

$a = - 14 , b = 6 \text{ and } {r}^{2} = 9 \Rightarrow r = 3$

$\Rightarrow \text{ centre " =(-14,6)" and } r = 3$