How do you find the center and radius for #x^2 + y^2 + 8y + 6 = 0#?
cetre at (0,-4)
The General Eqn. of a circle is given by
Comparing the given eqn. with the general one, we get,
Then, the centre is
Completing the squares of the given eqn., we have,
Now recall that eqn. of a circle with centre
Comparing (1) & (2), we get the cetre at (0,-4)