Question

How do you find the critical numbers of `1/(t^2+3)`?

Answer 1

The on;y critical number is `0`.

Explanation:

`f(t) = 1/(t^2+3)`

`f'(t) = (-2t)/(t^2+3)^2`

`f'(t)` is never undefined and is `0` only at `t=0`