# How do you find the critical numbers of #9x^3 - 25x^2#?

##### 1 Answer

Jan 4, 2016

#### Answer:

#### Explanation:

Critical numbers are the

Find the derivative of

#d/dx(9x^3-25x^2)=27x^2-50x#

Set equal to

#27x^2-50x=0#

#x(27x-50)=0#

#x=0,50/27#

The derivative is never undefined so there are only two critical values at