# How do you find the critical points for # f(x) = x^4 + 2x^3#?

##### 1 Answer

Oct 12, 2017

@ x = -(3/2), It is concave up and the critical point is low and high @ x = 0.

graph{x^4+2x^3 [-10, 10, -5, 5]}

#### Explanation:

@ x = -(3/2), It is concave up and the critical point is low and high @ x = 0.