# How do you find the critical points for y= 2x^2 + 10x - 7?

Oct 10, 2016

$x = - \frac{5}{2}$

#### Explanation:

The critical points of a function are the numbers that make its first derivative equal to zero $\implies$ for $f \left(x\right)$, find $f ' \left(x\right)$ and equate it to $0$. The points that make $f ' \left(x\right) = 0$ are called "critical points. "

$y = 2 {x}^{2} + 10 x - 7$

$y ' = 4 x + 10$

$y ' = 0 \implies 4 x + 10 = 0$

$\implies 4 x = - 10$

$\implies 2 x = - 5$

$\implies x = - \frac{5}{2}$ is the critical point.

Hope this was helpful :)