Question

How do you find the critical points for `y= 2x^2 + 10x - 7`?

Answer 1

`x=-5/2`

Explanation:

The critical points of a function are the numbers that make its first derivative equal to zero `=>` for `f(x)`, find `f'(x)` and equate it to `0`. The points that make `f'(x)=0` are called "critical points. "

`y=2x^2+10x-7`

`y'=4x+10`

`y'=0=>4x+10=0`

`=>4x=-10`

`=>2x=-5`

`=>x=-5/2` is the critical point.

Hope this was helpful :)