# How do you find the critical points of #d'(x)=x^2+2x-4#?

##### 1 Answer

Jul 1, 2018

#### Answer:

#### Explanation:

We know that a function

#f'(x) = 0# #f'(x)# is undefined.

So, let's look for such cases in our function here. We've been given the derivative

*Note that since #d'(x)# is a polynomial, and polynomials are defined everywhere, we don't need to worry about finding where #d'(x)# is undefined.*

Since this doesn't factor, we'll need to use the quadratic formula:

Some quick simplification/cleaning up gives:

And there's your answers.

Hope that helped :)