How do you find the critical points of f'(x)=15-5x?

May 3, 2018

Critical point at $x = 3$.

Explanation:

Critical points occur at $c$ if $f ' \left(c\right) = 0$ or $f ' \left(c\right)$ does not exist.

$f ' \left(x\right) = 0$

So

$15 - 5 x = 0$

$15 = 5 x$

$x = 3$