How do you find the critical points of #g'(x)=3x^2-6x^2#?

1 Answer
Jul 24, 2017

Answer:

I can't tell you what the coordinate of your critical point is for that equation because I don't know what your original function is.

Explanation:

To find the critical point of an equation# f(x)#, you find its derivative #f'(x)# and set it equal to 0 and find the x-values. Then you plug those x-values into #f(x)# to get the coordinates of the critical values.

Remember, the critical value is at a point in the graph where there is a min/max.

I can't tell you what the coordinate of your critical point is for that equation because I don't know what your original function is.