How do you find the critical points of g'(x)=3x^2-6x^2?

Jul 24, 2017

Answer:

I can't tell you what the coordinate of your critical point is for that equation because I don't know what your original function is.

Explanation:

To find the critical point of an equation$f \left(x\right)$, you find its derivative $f ' \left(x\right)$ and set it equal to 0 and find the x-values. Then you plug those x-values into $f \left(x\right)$ to get the coordinates of the critical values.

Remember, the critical value is at a point in the graph where there is a min/max.

I can't tell you what the coordinate of your critical point is for that equation because I don't know what your original function is.