# How do you find the critical points of g'(x)=3x^2-6x^2?

To find the critical point of an equation$f \left(x\right)$, you find its derivative $f ' \left(x\right)$ and set it equal to 0 and find the x-values. Then you plug those x-values into $f \left(x\right)$ to get the coordinates of the critical values.