How do you find the cross product a × b given #a = ‹t,t^2,t^3›#, #b = ‹1, 6t, 8t^2› #? Precalculus Vectors in the Plane Vector Operations 1 Answer A. S. Adikesavan Apr 23, 2016 #a X b = < 2t^4, -7t^3, 5t^2 ># Explanation: If# a = < a_1. a_2, a_3 > and b = < b_1, b_2, b_3 >, a X b = < a_2b_3-a_3b_2, a_3b_1-a_1b_3, a_1b_2-a_2b_1 >#. Here, #a X b = < 8t^4-6t^4, t^3-8t^3, 6t^2-t^2 >=< 2t^4, -7t^3, 5t^2 >#. Answer link Related questions Question #b4ef9 What is meant by a component of a vector? How do I find the vertical component of a vector? How do i find the horizontal component of a vector? Is vector addition commutative? What happens when I multiply a vector by itself? What is the definition of vector addition? How do I do vector subtraction? What is a velocity vector? How can the law of cosines be used to find the magnitude of a resultant? See all questions in Vector Operations Impact of this question 4043 views around the world You can reuse this answer Creative Commons License