How do you find the cross product a × b given $a = ‹t,t^2,t^3›$ , $b = ‹1, 6t, 8t^2›$ ?

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Answer 1 · 2016-04-23T03:21:04

$a X b = < 2t^4, -7t^3, 5t^2 >$

If $a = < a_1. a_2, a_3 > and b = < b_1, b_2, b_3 >, a X b = < a_2b_3-a_3b_2, a_3b_1-a_1b_3, a_1b_2-a_2b_1 >$ .

Here, $a X b = < 8t^4-6t^4, t^3-8t^3, 6t^2-t^2 >=< 2t^4, -7t^3, 5t^2 >$ .

How do you find the cross product a × b given a = ‹t,t^2,t^3›a = ‹t,t^2,t^3›, b = ‹1, 6t, 8t^2› b = ‹1, 6t, 8t^2› ?