How do you find the cube root of 0.000343?

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Answer 1 · 2016-06-26T20:18:50

#root(3)(0.000343) = 0.07#

Note that #0.000343 = 343*10^(-6)# and #343=7^3#

So:

#root(3)(0.000343) = root(3)(343*10^(-6)) = root(3)(343)*root(3)(10^(-6))#

#= root(3)(7^3)*10^(-2) = 7*10^(-2) = 0.07#

Answer 2 · 2016-06-26T20:50:52

#0.07#

Group the decimals in three's from the decimal.
Each group must have one number.

#root(3)"0.000 343"#

#root(3)0.000 = 0#

#root(3)343 = 7#

#root(3)"0.000 343" = 0.07#

Check: 2 decimal places cubed will give 6 decimal places.