How do you find the definite integral for: #x^2 dx# for the intervals #[2, 5]#?
1 Answer
Jun 19, 2017
# int_2^5 \ x^2 \ dx = 39#
Explanation:
We use the standard power rule for integrals:
# int_2^5 \ x^2 \ dx = [x^3/3]_2^5 #
# " " = 125/3 - 8/3#
# " " = 117/3#
# " " = 39#
