Question

How do you find the definite integral of `int (2+3x-x^2) dx` from `[1,2]`?

Answer 1

It is

#int_1^2 (2+3x-x^2)dx=int_1^2 d/dx[2x+3/2x^2-x^3/3]dx= [2x+3/2x^2-x^3/3]_1^2=25/6#