# How do you find the derivative f (x) = x^6 · e^(7x)?

Feb 26, 2016

$f = {x}^{6} g = {e}^{7 x}$
$f ' = 6 {x}^{5} g ' = 7 {e}^{7 x}$
$f ' \left(x\right) = f g ' + g f '$
=$7 \left({x}^{6}\right) \left({e}^{7 x}\right) + 6 {e}^{7 x} {x}^{5}$