How do you find the derivative for #f (x) = -3ln2x#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Other Bases 1 Answer Michael Mar 27, 2015 #f'(x)=(-3)/(x)# #f(x)=-3ln(2x)# Applying the chain rule: #f'(x)=-3xx(1)/(2x)xx2=-3/x# Answer link Related questions How do I find #f'(x)# for #f(x)=5^x# ? How do I find #f'(x)# for #f(x)=3^-x# ? How do I find #f'(x)# for #f(x)=x^2*10^(2x)# ? How do I find #f'(x)# for #f(x)=4^sqrt(x)# ? What is the derivative of #f(x)=b^x# ? What is the derivative of 10^x? How do you find the derivative of #x^(2x)#? How do you find the derivative of #f(x)=pi^cosx#? How do you find the derivative of #y=(sinx)^(x^3)#? How do you find the derivative of #y=ln(1+e^(2x))#? See all questions in Differentiating Exponential Functions with Other Bases Impact of this question 5411 views around the world You can reuse this answer Creative Commons License