# How do you find the derivative for x(lnx)^2?

Us power rule to differentiate ${\left(\ln x\right)}^{2}$
$\frac{\mathrm{dy}}{\mathrm{dx}} = \left(\frac{d}{\mathrm{dx}} \left(x\right)\right) {\left(\ln x\right)}^{2} + x \left(\frac{d}{\mathrm{dx}} \left({\left(\ln x\right)}^{2}\right)\right)$
$\frac{\mathrm{dy}}{\mathrm{dx}} = {\left(\ln x\right)}^{2} + x \left[2 \left(\ln x\right) \left(\frac{1}{x}\right)\right]$
$\frac{\mathrm{dy}}{\mathrm{dx}} = {\left(\ln x\right)}^{2} + 2 \ln x$