# How do you find the derivative of #arcsin x + arccos x#?

##### 1 Answer

Jan 2, 2017

#### Explanation:

It may not at all be obvious but its worth remembering that:

#arcsinx+arccosx=pi/2#

To see why the review:

How do you prove

Using this we have:

# d/dx(arcsinx+arccosx)=0#

If you could not spot this little helper then you can show the result using the individual results:

#d/(dx) arcsinx = 1/sqrt(1 - x^2) #

#d/(dx) arccosx = -1/sqrt(1 - x^2) #

And so the result is obvious