Question

How do you find the derivative of `cos^2 (x^2 - 3x)`?

Answer 1

`(6-4x) cos (x^2-3x) sin (x^2 -3x)`

Explanation:

First differentiate cosine function w.r.t `x^2-3x` and then differentiate `x^2-3x` w.r.t x.............. Chain rule

Derivative would be `-2cos(x^2 -3x) sin(x^2-3x) (2x-3)`

`(6-4x) cos (x^2-3x) sin (x^2 -3x)`