How do you find the derivative of $cos[sqrt (x)]$ ?

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Answer 1 · 2015-10-28T02:08:38

$d/dx(sqrtx) =d/dx(x^(1/2)) =1/2x^(1/2-1)=1/2x^(1/2-2/2)=1/2x^(-1/2)=1/(2x^(1/2))= 1/(2sqrtx)$

$d/dx(cos(sqrtx)) = -sin(sqrtx) d/dx(sqrtx)$

$= -sin(sqrtx) (1/(2sqrtx))$

How do you find the derivative of cos[sqrt (x)]cos[sqrt (x)]?