# How do you find the derivative of f(x)=(x-1)(x-2)(x-3)?

$f ' \left(x\right) = \left(x - 2\right) \left(x - 3\right) + \left(x - 1\right) \left(x - 3\right) + \left(x - 1\right) \left(x - 2\right)$
$y = u v w$
$y ' = u ' v w + u v ' w + u v w '$