# How do you find the derivative of f(x) = (x^3)(e^x)?

Jun 20, 2015

$f ' \left(x\right) = {x}^{2} {e}^{x} \left(3 + x\right)$
$f \left(x\right) = h \left(x\right) g \left(x\right)$ derived gives you:
$f ' \left(x\right) = h ' \left(x\right) g \left(x\right) + h \left(x\right) g ' \left(x\right)$
$f ' \left(x\right) = 3 {x}^{2} {e}^{x} + {x}^{3} {e}^{x} = {x}^{2} {e}^{x} \left(3 + x\right)$