How do you find the derivative of #g(x)=3 arccos (x/2)#?
1 Answer
Jul 20, 2017
Explanation:
#•color(white)(x)cos^-1x=-1/sqrt(1-x^2)#
#"differentiate a composite function using the "#
#color(blue)"chain rule"#
#•color(white)(x)cos^-1(f(x))=-1/sqrt(1-(f(x))^2).f'(x)#
#g(x)=3cos^-1(x/2)#
#rArrg'(x)=3xx-1/sqrt(1-(x/2)^2)xx1/2#
#color(white)(rArrg'(x))=-3/(2sqrt(1-x^2/4))#
