Question

How do you find the derivative of `G(x)=int (t^2-3t)dt` from `[1,pi]`?

Answer 1

`G'(x) = 0`

Explanation:

The RHS with those limits is `int_1^pi(t^2-3t)dt` which evaluates to a constant number, hence it's derivative is `G'(x) = 0`