# How do you find the derivative of G(x)=int (t^2-3t)dt from [1,pi]?

$G ' \left(x\right) = 0$
The RHS with those limits is ${\int}_{1}^{\pi} \left({t}^{2} - 3 t\right) \mathrm{dt}$ which evaluates to a constant number, hence it's derivative is $G ' \left(x\right) = 0$