# How do you find the derivative of G(x)=int (tan(t^2))dt from [1,x^2]?

$G \left(x\right) = \int \tan {t}^{2} \setminus \mathrm{dt} q \quad \left[1 , {x}^{2}\right]$
$\text{ie } G \left(x\right) = {\int}_{1}^{{x}^{2}} \tan {t}^{2} \setminus \mathrm{dt}$
$G ' \left(x\right) = \tan \left({\left({x}^{2}\right)}^{2}\right) \left({x}^{2}\right) ' = 2 x \setminus \tan {x}^{4}$