Question

How do you find the derivative of Inverse trig function `f(x)= 7t-14cos(x)+20`?

Answer 1

See the explanation below.

Explanation:

First: there is no inverse trig function and this is not a trig function (although it involves one).

Second: Is `t` a typing error that should be `x` or is it another function of `x`?

For `f(x)= 7t-14cos(x)+20`,

we get use the chain rule to find `d/dx(7t) = 7dt/dx`,

we use the derivative of cosine to get `d/dx(-14cosx) = -14(-sinx) = +14sinx`.

Therefore,

`f'(x) = 7dt/dx+14sinx`.

For `t` a constant, this becomes `f'(x) = 14sinx`.

For `t=x`, this becomes `f'(x) = 7+14sinx`.