How do you find the derivative of $ln ({cos}^{2} (x))$ $ln(cos^2(x))$ ?

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Answer 1 · 2015-10-17T14:09:03

$- 2 tan x$ $-2tanx$

Using the chain rule:

$f'(x)=1/(cos^2x)* 2cosx * (-sinx) = -2 sinx/cosx = -2tanx$

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How do you find the derivative of ln(cos^2(x))ln(cos2(x))ln(cos^2(x))?