Question

How do you find the derivative of `p(y) = (y^-1 + y^-2)(5y^-3 + 9y^-4)`?

Answer 1

I found: `p'(y)=-54y^-7-70y^-6-20y^-5`

Explanation:

You can use the Product Rule to get:
`p'(y)=(-y^-2-2y^-3)(5y^-3+9y^-4)+(y^-1+y^-2)(-15y^-4-36y^-5)=`
`=-5y^-5-9y^-6-10y^-6-18y^-7-15y^-5-36y^-6-15y^-6-36y^-7=`
`=-54y^-7-70y^-6-20y^-5`