How do you find the derivative of #s=3^(t+1)#?

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Answer 1 · 2017-05-18T12:59:09

#(ds)/(dt)=(3^(t+1))ln3#

for these type of problems we use logarithmic differentiation

#s=3^(t+1)#

#=>lns=Ln(3^(t+1))#

#=>lns=(t+1)ln3#

differentiate wrt #t#

#1/s (ds)/(dt)=ln3#

#(ds)/(dt)=sln3#

substituting back for #s#

#(ds)/(dt)=(3^(t+1))ln3#