How do you find the derivative of $sin ^2 (2x) + sin (2x+1)$ ?

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Answer 1 · 2016-03-09T00:43:20

It is

$d/dx [sin ^2 (2x) + sin (2x+1)]=2sin2x(d/dx(sin2x))+d/dx[sin(2x+1)] =4*sin2x*cos2x+2*cos(2x+1)$

Finally

$d/dx [sin ^2 (2x) + sin (2x+1)]=4*sin2x*cos2x+2*cos(2x+1)$

How do you find the derivative of sin ^2 (2x) + sin (2x+1) sin ^2 (2x) + sin (2x+1) ?