How do you find the derivative of #sinx/x#?

1 Answer
Apr 16, 2015

You can use the quotient rule or the product rule.

Quotient Rule
#h(x) = f(x)/g(x)#
#h'(x) = (g(x)*f'(x) - f(x)*g'(x))/((g(x))^2)#

#h(x) = sinx/x#
#h'(x) = (x*(sinx)' - sinx*(x)')/(x^2) = (xcosx - sinx)/x^2#
#= cosx/x - sinx/x^2#

Product Rule
#h(x) = f(x)*g(x)#
#h(x) = f(x)*g'(x) + g(x)*f'(x)#

#h(x) = 1/x*sinx#
#h'(x) = 1/x*(sinx)' + sinx*(1/x)' = cosx/x - (sinx)/x^2#

As you can see, you still get the same result in the end.