How do you find the derivative of the function #f(x)=arcsin(4x)+arccos(4x)#?

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Answer 1 · 2015-05-14T10:24:29

Since the derivative of

#y=arcsin4x#

is

#y'=1/sqrt(1-16x^2)*4#

and the derivative of

#y=arccos4x#

is

#y'=-1/sqrt(1-16x^2)*4#,

The derivative of the function is #0#.