Question

How do you find the derivative of the function `y = arccos(e^(5x))`?

Answer 1

`y'(x)=-1/sqrt(1-(e^(5x))^2)*exp(5x)*5`

Explanation:

Note that

`(arc cos(x))'=-1/sqrt(1-x^2)`
then we get by the chain rule

`y'(x)=-1/sqrt(1-(e^(5x))^2)*5*e^(5x)`