How do you find the derivative of the function: #y= arccos( x^7+sqrt5 )#?
1 Answer
Jan 10, 2016
Explanation:
Use the chain rule:
#d/dx[arccos(u)]=-1/sqrt(1-u^2)*u'#
Thus, if
#d/dx[arccos(x^7+sqrt5)]=-1/sqrt(1-(x^7+sqrt5)^2)*d/dx[x^7+sqrt5]#
#=-1/sqrt(1-(x^7+sqrt5)^2)*7x^6#
#=(-7x^6)/sqrt(1-(x^7+sqrt5)^2)#
