Question

How do you find the derivative of `x = (1/3) (y^(1/2)) (y-3)`?

Answer 1

`=(2y^(1/2))/(y-1)`

Explanation:

Use `(dy)/(dx)=1/((dx)/(dy))`

`=1/(1/3(y^(1/2)+(y-3)(1/2y^(-1/2)))`

`=(2y^(1/2))/(y-1)`