# How do you find the derivative of  x = (1/3) (y^(1/2)) (y-3) ?

Oct 22, 2016

$= \frac{2 {y}^{\frac{1}{2}}}{y - 1}$
Use $\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{1}{\frac{\mathrm{dx}}{\mathrm{dy}}}$
=1/(1/3(y^(1/2)+(y-3)(1/2y^(-1/2)))
$= \frac{2 {y}^{\frac{1}{2}}}{y - 1}$