How do you find the derivative of #x(t)=5sint+3cost#?

1 Answer
Jim G.
Jan 26, 2017

#x'(t)=5cost-3sint#

Explanation:

Using the #color(blue)"standard derivatives for these terms"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(sinx)=cosx , d/dx(cosx)=-sinx)color(white)(2/2)|)))#

#x(t)=5sint+3cost#

#rArrx'(t)=5cost-3sint#

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