Question

How do you find the derivative of `xln^(3x)`?

Answer 1

Question does not make sense, as you cannot write a log to the power of something without anything inside the log.

ASSUMING you meant `xln(3x)`:

Let `f(x)=xln(3x)`

Use product rule to differentiate:
`f'(x)=x(3/(3x)) + (1)ln(3x)`
`f'(x)=1+ln(3x)`