How do you find the derivative of #y=1+x-cosx#?
1 Answer
Dec 26, 2016
Explanation:
differentiate using
#color(blue)"standard derivatives"#
#color(orange)"Reminder"#
#D(" constant" )=0color(white)(xxxx)D(x)=1#
#"and " D(cosx)=-sinx#
#y=1+x-cosxrArrdy/dx=0+1-(-sinx)#
#=1+sinx#
