Question

How do you find the derivative of `y= 2secx + tanx`?

Answer 1

`(dy)/(dx)=secx(2tanx+secx)`

Explanation:

Since there is only a simple addition operation, `2secx` and `tanx` can be derived independently.

`d/(dx)2secx=2secxtanx->`since `d/(dx)secx=secxtanx`

`d/(dx)tanx=sec^2x`

`:.(dy)/(dx)=2secxtanx+sec^2x=secx(2tanx+secx)`