How do you find the derivative of #y=2sinx+3cosx#?
1 Answer
Apr 10, 2018
Explanation:
#"using the "color(blue)"standard derivatives"#
#•color(white)(x)d/dx(sinx)=cosx" and "d/dx(cosx)=-sinx#
#rArrdy/dx=2cosx-3sinx#
