How do you find the derivative of $y=2sinx+3cosx$ ?

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Answer 1 · 2018-04-10T17:30:44

$"dy/dx=2cosx-3sinx$

$"using the "color(blue)"standard derivatives"$

$•color(white)(x)d/dx(sinx)=cosx" and "d/dx(cosx)=-sinx$

$rArrdy/dx=2cosx-3sinx$

How do you find the derivative of y=2sinx+3cosxy=2sinx+3cosx?