Question

How do you find the derivative of `y=(2x^2+3x+3)(x^2-5)`?

Answer 1

First expand the equation, then take the derivative normally.

Explanation:

`y = (2x^4 + 3x^3 + 3x^2 + 10x^2 + 15x + 15)`
`y = (2x^4 + 3x^3 + 13x^2 + 15x + 15)`
`dy/dx = 8x^3 + 9x^2 + 26x +15`