How do you find the derivative of #y = arcsin(x^5) #?

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Answer 1 · 2016-06-23T11:07:21

# y' = (5x^4)/(sqrt{1 - x^{10})#

#y = arcsin(x^5)#

#sin y = x^5#

#cos y \ y' = 5x^4#

# y' = (5x^4)/(cos y)#

# y' = (5x^4)/(sqrt{1 - sin^2 y})#

# y' = (5x^4)/(sqrt{1 - (x^5)^2})#

# y' = (5x^4)/(sqrt{1 - x^{10})#