How do you find the derivative of #y=cos^2theta#?

1 Answer
Jim G.
May 6, 2018

#dy/(d theta)=-sin2theta#

Explanation:

#"differentiate using the "color(blue)"chain rule"#

#"given "y=f(g(x))" then"#

#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#

#y=cos^2theta=(costheta)^2#

#rArrdy/(d theta)=2costhetaxxd/(d theta)(costheta)#

#color(white)(xxxxx)=-2sinthetacostheta#

#color(white)(xxxxx)=-sin2theta#

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