How do you find the derivative of $y = sin x \cdot cos x$ $y=sinx*cosx$ ?

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Answer 1 · 2017-04-22T01:52:13

$\frac{d y}{d x} = cos 2 x$ $dy/dx= cos2x$

We can write:

$y = sin x cos x$ $y= sinx cosx$

As:

$y = \frac{1}{2} sin 2 x$ $y= 1/2sin2x$

Differentiating wrt $x$ $x$ we get:

$\frac{d y}{d x} = \frac{1}{2} cos 2 x \cdot 2$ $dy/dx= 1/2cos2x*2$
$= cos 2 x$ $" "= cos2x$

How do you find the derivative of y=sinx⋅cosxy=sinx*cosx?