How do you find the derivative of #y=sinx*cosx#?
1 Answer
Apr 22, 2017
# dy/dx= cos2x#
Explanation:
We can write:
# y= sinx cosx #
As:
# y= 1/2sin2x#
Differentiating wrt
# dy/dx= 1/2cos2x*2#
# " "= cos2x#
