How do you find the derivative of #y=tan^2(3x)#?
1 Answer
Sep 8, 2014
By using the Chain Rule twice,
#y'=6tan(3x)sec^2(3x)#
Let us look at some details.
By Chain Rule,
#y'=2tan(3x)cdot(tan(3x))'#
by another application of Chain Rule to
#=2tan(3x)cdot sec^2(3x)cdot3#
by cleaning up a bit,
#=6tan(3x)sec^2(3x)#
